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0.6x^2-27x-2=0
a = 0.6; b = -27; c = -2;
Δ = b2-4ac
Δ = -272-4·0.6·(-2)
Δ = 733.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{733.8}}{2*0.6}=\frac{27-\sqrt{733.8}}{1.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{733.8}}{2*0.6}=\frac{27+\sqrt{733.8}}{1.2} $
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